Without adding, find the sum. (i) 1 + 3 + 5 + 7 + 9 (ii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 +19 (iii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
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5
i) Total consecutive odd numbers = 5
Thus n = 5
Therefore sum = n2
= 5*5 = 25
ii)
Total consecutive odd numbers = 10
Thus n = 10
Therefore sum = n*n
= 10*10 = 100
iii)
Total consecutive odd numbers = 12
Thus n = 12
Therefore sum = n*n
= 12*12 = 144
Answered by
0
You need to calculate the all sum....... by calculator.
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