Question

without adding find the sum of 2+4+6+8+10+12+14+16+18+20​

Answer 1

HeRe Is Your Ans ⤵

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$sum = \frac{n}{2} (2a + (n - 1)d) \\ \\ = > \frac{10}{2} (2 \times 2 + 9 \times 2) \\ \\ = > 5(4 + 18) \\ \\ = > 5 \times 22 \\ \\ = > 110$

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Answer 2

HEY MATE:

GIVEN HERE.

2+4+6+8+10+12+14+16+18+20.

this form of AP.

so , here a=2,d=2,n=10

using formula:

==>s=n/2[2a+(n-1)d]

==>s=10/2[2*2+(10-1)*2]

==>s=5[4+18]

==>s=5*22

==>s=110.

so..

sum of all above number will be:

. =110.

I hopes its helps u.

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