without any calculation find the number of digit in the square root of each of the following numbers 961 and 4489
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No. of digits in the square root of 961 is 2 and 4489 is 2.
To find out the no. of digits in the square root of a no., the formula for even nos. is (n/2) and for odd nos. is(n+1)/2.
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To find out the no. of digits in the square root of a no., the formula for even nos. is (n/2) and for odd nos. is(n+1)/2.
Hope it helps.
Please mark my answer as brainliest.
Thank You.
ShaadabShamim:
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yadavkumar Please mark my answer as brainliest.
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