Question

Without any calculation find the number of digits in the square root of each of the following number its questions is 961

Answer 1

Answer:

the formula for no of diguts in square root is

n/2( if the no of digts in square is even)

n+1/2( if the no of digts in square is odd)

so the no of digts in 961 is 3

n+1/2

=3+1/2

=4/2=2

theeefore no of digits in square root of 961 is 2