Question

without calculating square roots find the number of digits in the square root of 7225​

Answer 1

Answer:

Once again, the square root of 7225 is 85.

Answer 2

Answer:

Solution:

(i) Here, 64 contains two digits which is even.

Therefore, number of digits in square root = \frac{n}{2}=\frac{2}{2}=1

(ii) Here, 144 contains three digits which is odd.

Therefore, number of digits in square root = \frac{n+1}{2}=\frac{3+1}{2}=\frac{4}{2}=2

(iii) Here, 4489 contains four digits which is even.

Therefore, number of digits in square root = \frac{n}{2}=\frac{4}{2}=2

(iv) Here, 27225 contains five digits which is odd.

Therefore, number of digits in square root = \frac{n}{2}=\frac{5+1}{2}=3

(v) Here, 390625 contains six digits which is even.

Therefore, number of digits in square root = \frac{n}{2}=\frac{6}{2}=3