without calculating the cubes find 20^3+10^3-30^3
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HEYA.....YOuR...ANSWER IS HERE
6000+1000-9000=-2000
HOPE THIS WILL HELP YOU
mark me as brainliest plz
6000+1000-9000=-2000
HOPE THIS WILL HELP YOU
mark me as brainliest plz
Answered by
1
Heya Dear,
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Q. Without calculating the cubes find 20³ + 10³ - 30³.
Let ( a = 20, b = 10 , c = -30 ).
Now add a,b and c.
⇒ a + b + c = 20 + 10 - 30
⇒ a + b + c = 30 - 30
∴ a + b + c = 0.
Using identity if ( a + b + c = 0 ), then a³ + b³ + c³ = 3abc.
= a³ + b³ + c³
= 3 abc
= 3 × 10 × 20 × ( -30 )
= -18,000.
Hope it helps !
By : Vaibhav
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Q. Without calculating the cubes find 20³ + 10³ - 30³.
Let ( a = 20, b = 10 , c = -30 ).
Now add a,b and c.
⇒ a + b + c = 20 + 10 - 30
⇒ a + b + c = 30 - 30
∴ a + b + c = 0.
Using identity if ( a + b + c = 0 ), then a³ + b³ + c³ = 3abc.
= a³ + b³ + c³
= 3 abc
= 3 × 10 × 20 × ( -30 )
= -18,000.
Hope it helps !
By : Vaibhav
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