Without calculating the square root find the the number of digits in the square root of 81
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Let n denotes the number of digits in a number.
1. if n is even, the number of digits in the square root of the number will be (n/2).
2. If n is odd, the number of digits in the square root of the number will be (n+1)/2
In case of 81, n = 2 (even),
hence number if digit in its square root will be
n/2 = 2/2 = 1
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