Math, asked by trishu, 1 year ago

without directly multiplying  evaluate the following
a) 0.99 x 0.99
b) 0.64 x 0.64-0.36 x 0.36
c) 1.54 x 1.54+ 2 x 1.54 x 1.46 + 1.46  x 1.46
d) 3.53 x 3.53-3.47x3.47
            0.06
e)   6.82 x 6.82-1.18 x 1.18
               5.64


sam11oscar: the largest 5 digit no is 99999. when it is divided by 8 it leaves a remainder 7. but we need remainder as 5.so reduce 2 (7-5) from 99999. ie,99997 is the largest 5 digit no which when divided by 8 leaves a remainder 5 and which when divided by 7 leaves a remainder 2.

Answers

Answered by thinkdifferent
9
1) 0.99^2 = (1- 0.01)^2 = 1 -2x 1x0.01 + 0.01^2 = 1-0.02 + 0.0001 = 0.9801ans. 2) 0.64^2 - 0.36^2 = (.64+.36)(.64-.36)= 1x.28 = 0.28answer Same properties in other questions

sam11oscar: the largest 5 digit no is 99999. when it is divided by 8 it leaves a remainder 7. but we need remainder as 5.so reduce 2 (7-5) from 99999. ie,99997 is the largest 5 digit no which when divided by 8 leaves a remainder 5 and which when divided by 7 leaves a remainder 2.
Answered by Anonymous
6
1. 0.99 x 0.99 = 0.9801
2. 0.64 x 0.64-0.36 x 0.36 = 0.28
3. 
1.54 x 1.54+ 2 x 1.54 x 1.46 + 1.46  x 1.46 = 9
4. 
3.53 x 3.53-3.47x3.47  = ?
            0.06
5. 
 6.82 x 6.82-1.18 x 1.18  = ?
               5.64

Sorry I don't know the answers of 4 and 5

Anonymous: mark as the best answer plz
thinkdifferent: It's not too hard I'll explain
thinkdifferent: (3.53+3.47)(3.53-3.47)/0.06=7x0.06/0.06=7 answer
thinkdifferent: 5th is same as 4
sam11oscar: the largest 5 digit no is 99999. when it is divided by 8 it leaves a remainder 7. but we need remainder as 5.so reduce 2 (7-5) from 99999. ie,99997 is the largest 5 digit no which when divided by 8 leaves a remainder 5 and which when divided by 7 leaves a remainder 2.
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