Without dividing, select and write down the number which are divisible by 3. (81, 102, 164, 189, 352, 372, 466, 756, 951, 1029 )
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2
81
102
189
372
756
951
1029
the sum of the digits of the numbers are divisible by 3
102
189
372
756
951
1029
the sum of the digits of the numbers are divisible by 3
shanaya22:
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Answered by
3
sum of the digits are divisible by 3 then that number is divisible by 3
81 , sum of the digits = 8+1 = 9 is divisible by 3
therefore 81 is divisible by 3
same way 102 ,189,372,756,951,and 1029 are divisible by 3
81 , sum of the digits = 8+1 = 9 is divisible by 3
therefore 81 is divisible by 3
same way 102 ,189,372,756,951,and 1029 are divisible by 3
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