Question

without doing actual division check whether x^3_4^2+x+6 Is divisible by x^2 -x-2

Answer 1

Answer:

x_3

Step-by-step explanation:

actual division check whether x^3_4^2+x+6 Is divisible by x^2 -x-2

Answer 2

Step-by-step explanation:

${x}^{2} - x - 2 = 0 \\ {x}^{2} + 1x - 2x - 2 = 0 \\ x(x + 1) - 2(x + 1) = 0 \\ (x + 1)(x - 2) = 0\\ x + 1 = 0 \: \: \: x - 2 = 0 \\ x = - 1 \: \: \: \: \: x = 2 \\ \\ {x}^{3} - 4 {x}^{2} + x + 6 \\ {2}^{3} - 4 \times {2}^{2} + 2 + 6 \\ 8 - 16 + 2 + 6 \\ 16 - 16 = 0$

hence it is divisible