Question

without drawing actual graph , find the zeros of the following polynomial if any
(1) x²-2x-8​

Answer 1

x²-2x-8=0

⇒x²-4x+2x-8=0

⇒x(x-4)+2(x-4)=0

⇒(x-4)(x+2)=0

x=4 ,-2

Hence -2 and 4 are zeroes of this polynomial

Answer 2

Answer:

Given, x²-2x-8=0

${x}^{2} - 4x + 2x - 8 = 0 \\ x(x - 4) + 2(x - 4) = 0 \\ (x + 2)(x - 4) = 0$

It is satisfied when x= -2, 4

Zeroes are 4 and -2