Question

Without finding cubes, factorise: 1.(x-y)3 +(y-z)3 +(z-x)3

Answer 1

Step-by-step explanation:

(x-y)3 + (y-z)3 + (z-x)3 = 3(x-y)(y-z)(z-x)

[a3 + b3 +c3 = 3abc. ( ifa+b+c= 0)]

3(xy-xz-y2-yz)(z-x)

3(xyz-xz2-y2z-yz2-x2y+x2z-y2x-xyz)