Without finding discriminant show x^2+4 has no real roots
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We are talking about roots, so x² + 4 = 0
=> x² + 4 = 0
=> x² = -4
=> x = √-4 = ±2i
We know that,
Hence, x² + 4 = 0 has no real roots , It has imaginary roots ( i. e, +2i , -2i )
We are talking about roots, so x² + 4 = 0
=> x² + 4 = 0
=> x² = -4
=> x = √-4 = ±2i
We know that,
Hence, x² + 4 = 0 has no real roots , It has imaginary roots ( i. e, +2i , -2i )
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