Question

without finding the cubes factorise the value of x-y cube +y-z cube+ z -x cube​

Answer 1

Answer:

answer is 3(x-y)(y-z)(z-x)

Step-by-step explanation:

(x-y)³ + (y-z)³ + (z-x)³

here, a³+b³+c³ = 3abc

because a+b+c = x-y+y-z+z-x

= 0

(x-y)³+(y-z)³+(z-x)³ = 3(x-y)(y-z)(z-x)