without finding the cubes factorise (x-2y)3 +(2y-2)+(z-x)3
Answers
Answered by
4
In this case, a + b + c = 0. Therefore,
a ³+ b³+ c³ = 3abc
= 3(x - 2y)(2y - z)(z - x)
a ³+ b³+ c³ = 3abc
= 3(x - 2y)(2y - z)(z - x)
ramankashyap:
sorry this is not correct
Then what's the answer
try
Pl tell the answer
try your best
once more try
Give me hint
Similar questions