Question

without finding the cubes ,factorise
(x-2y)³+(2y-3z)³+(3z-x)³

Answer 1

heya ! here is it !

(x - 2y)^3 + (2y -3 z )^3 + (3z -x )^3 ---(1)

let a = x -2y ,b = 2y- 3z , c= 3z -x

a+b +c = x -2y + 2y-3z + 3z - x = 0

a+ b +c = 0

if a+b +c = 0

then ,a^3 + b^3 + c^3 = 3abc

so from (1)

(x - 2y) ^3 + (2y -3 z )^3 + ( 3z - x ) ^3

=3 ( x - 2y ) ( 2y - 3z ) ( 3z - x )

hope it helps!
thank you !

Answer 2

✔✔heya here is ur answer !!!

THANK YOU ✌✌

HOPE IT HELPS YOU ☺☺