Without finding the cubes, factorise (x - 3y) ³+ (3y - 7z)³ + (7z- x)³
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3(x-3y)(3y-7z)(7z-x)
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Answer:
let x-3y be a
3y-7z be b
7z-x be c
now a+b+c=x-3y+3y-7z+7z-x=0
and if aplus b plus c is 0 then acube plus bcube plus c cube =3abc
3(x-3y)(3y-7z) (7z-x)
I do hope that it was Useful
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