Question

Without finding the cubes , factorise (x-y)³+ (y-z)³+(z-x)³

Answer 1

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Answer 2

Answer:

3(x-y) (y-z) (z-x)

Step-by-step explanation:

we know a³+b³+c³=(a+b+c) (a²+b²+c²-ab-bc-ca)

if a+b+c=0 then a³+b³+c³=3abc

x-y+y-z+z-x=0                           [ x-x+y-y+z-z ]

∴ (x-y)³+ (y-z)³+(z-x)³=3(x-y) (y-z) (z-x)