Without finding the cubes find the value of {1/4} 3 +{1/3} 3 -{7/12} 3
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Answered by
12
(1/4)^3 + (1/3)^3 - (7/12)^3
taking cube common,
=(1/4+1/3-7/12) ^3
=(3+4-7/12) ^3
=(0/12)^3
=0
taking cube common,
=(1/4+1/3-7/12) ^3
=(3+4-7/12) ^3
=(0/12)^3
=0
Answered by
6
Answer: -7/48
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