Without finding the roots, comment on the nature of roots, comment on the nature of the equation 2(x^2- x) = 3
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2(x^2-x) = 3
2x^2 -2x= 3
2x^2-2x-3 = 0
Here,
a = 2 b= -2 c = -3
b^2 -4ac = D
= (-2)^2 - 4(2)(-3)
=4 + 24
= 28
Since D > 0 this equation has real but distinct roots.
This is quadratic equation.
Hope it helps.
2x^2 -2x= 3
2x^2-2x-3 = 0
Here,
a = 2 b= -2 c = -3
b^2 -4ac = D
= (-2)^2 - 4(2)(-3)
=4 + 24
= 28
Since D > 0 this equation has real but distinct roots.
This is quadratic equation.
Hope it helps.
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