Question

Without finding the roots comment on the nature of the roots of the quadratic

equation: 9a2b2x2-48abcdx+64c2d2=0 a, b is not equal to 0​

Answer 1

Answer:

⇒ 9a

2

b

2

x

2

−24abcdx+16c

2

d

2

=0

⇒ Here, A=9a

2

b

2

,B=−24abcd,C=16c

2

⇒ B

2

−4AC

⇒ (−24abc)−4(9a

2

b

2

)(16c

2

d

2

)

⇒ 576a

2

b

2

c

2

d

2

−576a

2

b

2

c

2

d

2

⇒ 0

∴ Discriminant=0

⇒ Hence, roots of given quadratic equation are real and equal.

Step-by-step explanation:

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