Question

without finding the value of roots alfa and bita of polynomial p(x)=x²-5x+6
Find the valve of 1/alfa+1/bita and
alfa³+bita³
​

Answer 1

Step-by-step explanation:

x² - 5x + 6 =0

x² - 3x - 2x + 6=0

x(x-3) - 2(x-3) =0

(x-3) (x-2) =0

x=3 , x=2

a= 3 b= 2

sum of zeroes

a+b= -b/a

3+2=-(-5)/1

5=5

Product of zeroes

a. b= C/a

3×2= 6/1

6=6