Question

Without finding the zeroes a and ß of the polynomial p(y) = y² - 8y - 20 find the values of a+ß and a.ß​

Answer 1

Answer: 8 and -20

Step-by-step explanation:

Let p(y) be in the form (y - α)(y - β)

y - a = 0 ⇒ y = α

y - b = 0 ⇒ y = β

Hence the zeros of (y - α)(y - β) would be α and β

y² - 8y - 20 = (y - α)(y - β)

We know

(y - α)(y - β) = y² - βy - αy + αβ = y² - (α + β)y + αβ

Therefore

y² - 8y - 20 = y² - (α + β)y + αβ

α + β = 8

αβ = -20

Hope it helped