Question

without finding the zeroes Alpha and beta of the polynomials p(x)=3x² —10x+7, find the values of Alpha ,beta​

Answer 1

Answer:

We know that,

coffiecient of x²= alpha

and coffiecient of x is beta

so,

alpha be the 3,

and beta be the -10 ans completed

Answer 2

Answer:

alfa= 7/2 beta= 1

Step-by-step explanation:

3x^2+-10x+7=0

a=3, b=-10, c=7

b^2-4ac= 100-84=16

x= -b +-root (b^2 -4ac)/2a

x=-(-10)^2 +- (16)/6

alfa= 10+4/6 , beta= 10-4 /6

=14/6 ,beta = 6/6

=7/2 , beta= 1