without performing a actual long division how we can find that 13/3125 is terminating?
Answers
Answered by
1
we will break the denominator into the product of the primes....
that is, 3125 = 5^5 * 2^0 (any number with power 0 = 1)
as 3125 can be expressed in the form of 2^n*5^n, therefore, the given fraction is terminating.
that is, 3125 = 5^5 * 2^0 (any number with power 0 = 1)
as 3125 can be expressed in the form of 2^n*5^n, therefore, the given fraction is terminating.
Answered by
1
prime factorise 3125
3125 / 5 = 625 / 5= 125 / 5 =25 / 5 = 5 /5 = 1
if after prime factorization denominator has 5n * 2n it will terminate
in this case we can multiply numerator and denominator by 2^5
13 * 2^5 / 5^5 * 2^5
3125 / 5 = 625 / 5= 125 / 5 =25 / 5 = 5 /5 = 1
if after prime factorization denominator has 5n * 2n it will terminate
in this case we can multiply numerator and denominator by 2^5
13 * 2^5 / 5^5 * 2^5
Similar questions