Question

without solving comment on the nature of the roots by discriminant :x^2-ax-b^2​

Answer 1

Answer:

real and distant....

I hope it will benefit you buddy....

Answer 2

Explanation:

We have been given a quadratic equation with variable x .

→x^2 - ax - b^2 = 0 ←..... (1)

The general form of a quadratic equation is

A x^2 + B x + C = 0 ..........(2)

Equating equations (1) and (2) , we have

A = 1

B = - a

And ,

C = - b^2

The discriminant is given by = B^2 - 4AC

Hence , the discriminant of the given equation will be

= a^2 + 4 b^2

Since , a^2 ≥ 0 and , 4 b^2 ≥ 0

Hence. a ^2 + 4 b^2 ≥ 0

→ Discriminant is greater than or equal to zero .

Hence ,the equation will have Real

Roots.