Question

without solving examine the natural of rootsof the equation (2).4x²+3x-1=0​

Answer 1

Answer:

Distinct real roots

Step-by-step explanation:

We know Discriminant-D

D=b^2 -4ac

Here a=4 b=3 c=-1

D=3^2 -4×4×1

D=9-8

D=1

Since D is greater than zero,we have distinct real roots

Answer 2

Answer:

The nature of the roots of the given equation is two distinct real numbers

Step-by-step explanation:

The given equation is,

4x^2 + 3x -1 = 0

Let us compare the equation to the standard equation, ax^2 + bx + c = 0

Then a= 4, b= 3, c= -1

Now we know discriminant of a quadratic equation is = b^2 - 4ac

Now, for the given quadratic equation discriminant is = 3^2-4×4×(-1) = 9+16= 25>0

So, for the given equation the discriminant is strictly greater than 0 ,

So the roots of the given equation are two distinct real numbers