Question

without solving examine the nature of roots of equation X square - 6 X + 9 is equal to zero

Answer 1

to examine the nature of its roots we will determine it's discriminant

D=b^2-4ac

=36-36=0

Since the discriminant is 0

the equation has equal and real roots

Answer 2

Answer:

we will use the discriminant of the formula

i.e b^2 - 4 * a * c and will write in the form

ax^2+bx+c=0.

Step-by-step explanation:

so , here we have...

a=1, b=6, c=9

then, by putting value in the equation b^2-4*a*c..

we get,

= -6^2 - 4 * 1 * 9

= 36-36

= 0

so the roots are real and equal roots....

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