Question

Without solving find nature of root:4x²-4x+1=0​

Answer 1

Step-by-step explanation:

in this equation ,

a = 4, b= 4 and c= 1

so,

b² - 4ac

( 4 )² - 4 * 4 * 1

16 - 16

since b² - 4ac = 0 therefore this equation has real and equal roots

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Answer 2

Answer:here a=4, b=-4 and c=1

b^2-4ac

=(-4)^2 - 4×4×1

=16 - 16

=0

Therefore, nature of root is real and equal. Since, b^2-4ac =0