Question

without solving find the nature of the roots 5x^2-3x-4=0​

Answer 1

hey mate ,

Since the constants sign is negative and the 'b' sign is also negative Thus we can say that sum of roots if negative and also the product .. so for this The Roots should be One positive and another negative ... Further you can find the nature by finding D which is equal to B^2 - 4AC ...

here D>0 Thus roots are Real and unequal !!!

Hope you find it helpful!!

Do mark it as brainliest!!!

Answer 2

Step-by-step explanation:

5x²-3x-4=0

D=b²-4ac

=(-3)² -4(5) (-4)

=89

D>0

Hence,it is real and unequal