Question

without solving, state the nature of roots of 2x^2+6x+3=0

Answer 1

Answer:

The roots are real and distinct.

Step-by-step explanation:

we have to use the discriminant (d) to find the nature of the roots.

formula: d=b²-4ac.

here, b²-4ac=36-4(2)(3) =36-24=12>0

since it's greater than 0, the roots are real and distinct.