Question

Without solving the equation find the nature of the rooots of the quadratic equation root under2x²-5 √3+2√2=0

Answer 1

on comparing this equation with standard form of quadratic equation ax²+bx+c =0

we get

a= 2 , b= -5√3 , c= 2√2

Discriminant D = b²-4ac

b²-4ac = (-5√3)²- 4×2×2√2 = 75- 16√2

here our D >0

hence it have real and distinct roots