Question

Without solving the equation find the value of p for which the equation has real and equal roots (p - 4)x2 + 2px + 18 = 0​

Answer 1

Step-by-step explanation:

Using D=b^2-4ac

(2p)^2-4(p-4)×18=0

solve now please

Answer 2

Answer:

Step-by-step explanation:

(p - 4)2 + 2px + 18 = 0​

b^2-4ac=0

a=p-4 b=2p c=18

(2p)^2-4into (p-4) into 18

calculate