Math, asked by priyayadav2290, 8 months ago

Without solving the following quadratic equation, find the value of 'p' for which the roots are equal.

px² - 4x + 3

izuku57: hi

Answers

Answered by Vaibhavhoax

Given equation is,

px² - 4x + 3 = 0

comparing with. ax² + bx + c = 0

we get,

a = p, b = -4, c = 3

since roots are equal.

therefore,

D = 0

= b² - 4ac = 0

= 16 - 4p (3) = 0

= 12p = 16

= p = 4/3.

it helps you,

thanks.

izuku57: I got up with the question and see its already there the answer now my doubt is gone thank you for helping me good night dear

Vaibhavhoax: :)

izuku57: ( ° 〰️ ° )

Answered by izuku57

ANSWER :

GIVEN EQUATION IS

Px2 - 4x +3=0

COMPARING WITH

ax2 +bx+c =0

WE GET,

A=P, B=-4, C=3

SINCE ROOTS ARE EQUAL

THEREFORE,

D=0

=>B2 - 4AC=0

=> 16-4P (3)=0

=> 12P=16

=> P=4/3 ANSWER.

I HOPE THIS ANSWER HELPFUL TO YOU

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