Without solving the following quadratic equation, find the value of 'm' for which there
equation has real and equal roots. r? + 2(m-1)x+(m +5)=0 An
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Answer:
The given equation is x
2
+2(m−1)x+(m+5)=0
For the equation to have real and equal roots, the discriminant should be 0.
∴[2(m−1)]
2
−4(m+5)=0
⇒4(m
2
−2m+1)=4(m+5)
⇒m
2
−3m−4=0
⇒(m−4)(m+1)=0
∴m=4 or m=−1
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Answer:
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