without solving the quadratic equation, find the value of m for which the given equation has real and equal roots:xsquare +2 (m-1)x+(m+5)=0
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Since the equation has real and equal roots
Therefore DISCRIMINENT = 0
b^2 - 4ac= 0
4(m^2 +1 - 2m) - 4(1)(m+5) =0
4m^2 + 4 - 8m - 4m - 20= 0
4m^2 - 12m - 16 = 0
4m^2 - 16m + 4m - 16 =0
4m(m-4)+4(m-4)=0
(m-4)(4m+4)=0
m = 4 and - 1
Hope it help you
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Therefore DISCRIMINENT = 0
b^2 - 4ac= 0
4(m^2 +1 - 2m) - 4(1)(m+5) =0
4m^2 + 4 - 8m - 4m - 20= 0
4m^2 - 12m - 16 = 0
4m^2 - 16m + 4m - 16 =0
4m(m-4)+4(m-4)=0
(m-4)(4m+4)=0
m = 4 and - 1
Hope it help you
Please mark as brainliest if you liked the solution
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