Question

Without using derivatives, find the maximum and minimum value of y = |3sinx + 1|

Answer 1

y = | 3Sinx+1 |

Maximum and minimum values of Sinx = {-1,1} respectively .

Thus value of the given function will be maximum and minimum at only these points .

Put sinx = -1
y = | 3×(-1)+1 | => 2

Now, put sinx = 1
y = | 3×1 + 1 | => 4


This maximum and minimum values of the given function are 4 and 2 respectively .

Answer 2

Answer:

Maximum value = 4

Minimum value = 2.

Step-by-step explanation:

3sin x can vary from -3 ( at x = 3pie/2)  to +3( at x =pie/2)

So y = | 3 sinx + 1| takes maximum value when x =  pie/2

minimum at x = 3pie/2 .  

Maximum value = | 3 + 1 |  = 4

Minimum value = | -3 + 1| = |-2| = 2