without using distance formula show that the points (-2,-1)(4,0) (3 ,3) and (-3,2) are verti ces of a parallelogram
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Let the vertices be A(-2, -1), B(4, 0), C(3, 3), D(-3, 2)
Now mAB = mCD ⇒ AB || CD
and mBC = mAD ⇒ BC || AD
Hence ABCD is a parallelogram.
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