Question

without using if-else statement and ternary operators, accept three unequal numbers and display the second smallest number In java

Answer 1

class Second
{
public static void main(String args[])
{
Scanner in= new Scanner(System.in);
System.out.println("Enter three unequal numbers");
int a= in.nextInt();
int b=in.nextInt();
int c=in.nextInt();
int sec= Math.max(Math.min(a,b),Math.min(Math.max(a,b),c);
System.out.println("The second smallest number is" + sec);
}
}

Answer 2

Explanation:

import java.io.*;

class Second{

public static void main(String args[])throws IOException{

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

System.out.print("Enter first number: ");

int a = Integer.parseInt(br.readLine());

System.out.print("Enter second number: ");

int b = Integer.parseInt(br.readLine());

System.out.print("Enter third number: ");

int c = Integer.parseInt(br.readLine());

int sum = a + b + c;

int max = Math.max(a, b);

max = Math.max(max, c);

int min = Math.min(a, b);

min = Math.min(min, c);

int s = sum - max - min;

System.out.println("Second smallest number: " + s);

}

}