Question

without using paythagoras theorem , show that point A(0,4) B(1,2) and C(3,3) are the vertices of right angled traingle.

Answer 1

HIII!!!

YOUR SOLUTION IS HERE!!!!!!!!

WITHOUT USING PYTHAGORAS THEOREM

SLOPE OF AB× SLOPE OF BC = -1

SLOPE FORMULA:-
$y2 - y1 \div x2 - x1$
$- 2 \div 1 \times 1 \div 2 = - 1$
$- 1 = - 1$
HENCE PROVED THAT AB IS PERPENDICULAR TO BC .
THEREFORE TRIANGLE ABC IS RIGHT ANGLED TRIANGLE.

PLZ#FOLLOW#VIRATANMOL

Answer 2

Step-by-step explanation:

Given points = ( 0, 4 ) ; ( 1 , 2 ) ; ( 3 , 3 )

\text{Slope of any line = }\dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}Slope of any line =

x

2

−x

1

y

2

−y

1

For the slope of ( 0 , 4 ) and ( 1 , 2 ),

For convenience, let's assume the points. On comparing the given situation with formula,

Taking x₁ = 0 , y₁ = 4 , x₂ = 1 , y₂ = 2

Applying formula

⇒ Slope = \dfrac{2-4}{1-0}

1−0

2−4

⇒ Slope = - 2

For the slope of ( 1 , 2 ) and ( 3 , 3 ),

For convenience, let's assume the points. On comparing the given situation with formula,

Taking x₁ = 1 , y₁ = 2 , x₂ = 3 , y₂ = 3

Applying formula

⇒ Slope = \dfrac{3-2}{3-1}

3−1

3−2

⇒ Slope = - 1 / 2

We know that two lines with negative of their reciprocal slopes are perpendicular to each other.

Hence, proved.

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