Without using tables evaluate : 4sin72degree/cos 18 degree - 3 sec34 degree/cosec56 degree 3
Answers
Answered by
4
Step-by-step explanation:
Given:
sin234∘+sin256∘+2tan18∘tan72∘−cot230∘
=sin234∘+sin2(90∘−34∘)+2tan18∘tan(90∘−18∘)−cot230∘
=sin234∘+cos234∘+2tan18∘cot18∘−(3)2
=1+2tan18∘×tan18∘1−3
=1+2−3
=0
Answered by
1
Answer:
Given:
sin234∘+sin256∘+2tan18∘tan72∘−cot230∘
=sin234∘+sin2(90∘−34∘)+2tan18∘tan(90∘−18∘)−cot230∘
=sin234∘+cos234∘+2tan18∘cot18∘−(3
)2
=1+2tan18∘×tan18∘1−3
=1+2−3
=0
Step-by-step explanation:
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