Without using the trignometic tables, find i) cos 75°
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Notice that 75° = 30° + 45°, so we can rewrite cos(75°) as cos(30° + 45°), and use our angle sum identity.
cos(75°) = cos(30° + 45°) = cos(30°) ⋅ cos(45°) - sin(30°) ⋅ sin(45°)
Now, we just plug in our sine and cosine values for 30° and 45° and simplify.
cos(30°) ⋅ cos(45°) - sin(30°) ⋅ sin(45°)
= (√(3) / 2) ⋅ (√(2) / 2) - (1/2) ⋅ (√(2) / 2)
= √(6) / 4 - √(2) / 4
= (√(6) - √(2)) / 4
We get that the exact value of cos(75°) is (√(6) - √(2)) / 2.
cos(75°) = cos(30° + 45°) = cos(30°) ⋅ cos(45°) - sin(30°) ⋅ sin(45°)
Now, we just plug in our sine and cosine values for 30° and 45° and simplify.
cos(30°) ⋅ cos(45°) - sin(30°) ⋅ sin(45°)
= (√(3) / 2) ⋅ (√(2) / 2) - (1/2) ⋅ (√(2) / 2)
= √(6) / 4 - √(2) / 4
= (√(6) - √(2)) / 4
We get that the exact value of cos(75°) is (√(6) - √(2)) / 2.
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