without using trignometric table, prove that:
(i)sin 53 . cos 37 + cos 53 sin 37 =1
(ii)cos 54.cos 36-sin 54 .sin 36 =0
(iii)sec 70. sin 20 + cos20 .cosec 70 =2
(iv)(sin+ cos 18)(sin 72 + cos 18)=0
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sin53xcos37+cos53xsin37=1
LHS
sin(90-37)xcos37+cos(90-37)xsin37
cos37xcos37+sin37xsin37 [by formula]
cos²37+sin²37[by the formula ]
1
hence, LHS=RHS
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