without using Trigonometric Table evaluate sec 19 / Cos Sector 17 + 1/Root 3 × tan 39 × tan 25 × tan 30 × sin 65×tan 51 - 3 ( sin square 41 + sin square 49)
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Hi,
Sin 18°/cos 72° + √3 [tan10 tan 30 tan 40 tan 50 tan 80]
=Sin 18°/cos(90-72) + √3 [tan10 tan 30 tan 40 tan(90-50) tan(90-80)]
=Sin 18°/Sin 18 + √3 [tan10 tan 30 tan 40 cot40 cot10]
=1 + √3 [tan10 tan 30 tan 40 1/tan40 1/tan10]
=1 + √3 [tan 30]
=1 + √3 [1/√3]
=1 + 1 = 2
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