Question

without using trigonometric tables 4tan60sec30+sin31sec59+cot59cot31/8sin^2 30-tan^2 45
Urgent plz fast

Answer 1

(4Tan60Sec30  + Sin31Sec59  + Cot59Cot31)/(8Sin²30  - Tan²45) = 1

Step-by-step explanation:

(4Tan60Sec30  + Sin31Sec59  + Cot59Cot31)/(8Sin²30  - Tan²45)

= (4(Sin60/Cos60)(1/(Cos30))  + Sin31/Cos59  + Cot59/Tan31)/(8Sin²30  - Tan²45)

= (4(Sin60/Cos60)(1/(Sin60))  + Sin31/Sin31  + Cot59/Cot59)/(8Sin²30  - Tan²45)

= (4Cos60  + 1 + 1)/(8Sin²30  - Tan²45)

= (4/2  + 2)/(2 - 1)

= 4/1

= 1

(4Tan60Sec30  + Sin31Sec59  + Cot59Cot31)/(8Sin²30  - Tan²45) = 1

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