Without using trigonometric tables evaluate,
7/2 cos70*/sin20* + 3/2 cos55*cosec35*/tan5*tan 25*tan 45*tan85*tan65*
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7/2 cos70/sin(90-70) + 3/2 cos55 cosec(90-55) / tan5 tan(90-65) tan45 tan(90-5) tan65
7/2 cos70/cos70 + 3/2 cos55 sec55/tan5*cot5*tan65*cot65*tan45 ( tan 45 = 1)
7/2+3/2/1*1
10/2 = 5
7/2 cos70/cos70 + 3/2 cos55 sec55/tan5*cot5*tan65*cot65*tan45 ( tan 45 = 1)
7/2+3/2/1*1
10/2 = 5
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Answer:
7/2 cos70/sin(90-70) + 3/2 cos55 cosec(90-55) / tan 5 tan(90-65) tan 45 tan(90-5) tan65
7/2 cos 70/ cos 70 + 3/2 cos 55 sec 55/tan 5*cot 5*tan65*cot 65*tan 45 ( tan 45 = 1)
7/2+3/2/1*1
10/2 = 5
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