Without using trigonometric tables ,evaluate :
Sec 19/cosec71 + 1/√3 *tan 39 *tan 25* tan 65* tan 51* -3(sin^2 41 + sin^2 49)
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=sec19/sec(90-71)+1/√3*tan39*cot(90-25)*tan65*cot(90-51)-(sin^2 41 +cos^2(90-49)
=sec19/sec19+1/√3*tan39*cot65*tan65*cot39-3(sin^2 41 + cos^2 41)
=1+1\√3tan39*1/tan65*tan65*1/tan39 - 3*1
=1+1/√3-3
=1/√3-2
=1+2√3÷√3
=sec19/sec19+1/√3*tan39*cot65*tan65*cot39-3(sin^2 41 + cos^2 41)
=1+1\√3tan39*1/tan65*tan65*1/tan39 - 3*1
=1+1/√3-3
=1/√3-2
=1+2√3÷√3
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