Math, asked by ryan101888, 10 months ago

Without using trigonometric tables evaluate the following:
cot 30°/sec30°+cosec30°/tan45°+2cos0°/sin30°+cos^2 45°​

Answers

Answered by sanishaji30
4

Answer:

Step-by-step explanation:

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Answered by abhi178
1

value of given expression is 0.

we have to evaluate,

cot30°/sec30° + cosec30°/tan45° - 2cos0°/sin30° + cos²45°

we know, cot30° = √3, sec30° = 1/cos30° = 2/√3

cosec30° = 1/sin30° = 2 , tan45° = 1

cos0° = 1 , sin30° = 1/2 and cos45° = 1/√2

now, cot30°/sec30° + cosec30°/tan45° - 2cos0°/sin30° + cos²45°

= (√3)/(2/√3) + 2/1 - 2 × 1/(1/2) + (1/√2)²

= 3/2 + 2 - 4 + 1/2

= (3 + 1)/2 - 2

= 2 - 2

= 0

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