Math, asked by siddharth77810, 1 year ago

Without using trigonometric tables,find the value of cos 70/sin 20+cos 57.cosec 33-2 cos 60

Answers

Answered by abhimaths14
19

Answer:

Step-by-step explanation:

Attachments:
Answered by mysticd
25

Answer:

Value \:of \\\frac{cos70}{sin20}+cos57\cdot cosec33-2cos60=1

Step-by-step explanation:

Value \:of \\\frac{cos70}{sin20}+cos57\cdot cosec33-2cos60

=\frac{cos(90-70)}{sin20}+cos57\cdot cosec(90-57)-2cos60

=\frac{sin20}{sin20}+cos57\cdot sec57-2\times \frac{1}{2}

/* we know that,

i) cosA × secA = 1

ii) cos60° = 1/2 */

=1+1-1\\=1

Value \:of \\\frac{cos70}{sin20}+cos57\cdot cosec33-2cos60=1

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