Question

without using trigonometric tables sec 31° sin 59° + cos 31° cosec 59° =2

Answer 1

Hi ,

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We know that ,

1 ) sec( 90 - A ) = cosecA

2 )cos( 90 - A ) = sinA

3 ) cosecAsinA = 1

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LHS = sec31° sin59° + cos31°cosec59°

= Sec( 90-59)sin59+cos(90-59)cosec59

= Cosec59sin59+sin59cosec59

= 1 + 1

= 2

= RHS

I hope this helps you.

:)

Answer 2

Step-by-step explanation:

LHS

= sec 31 sin (90-31) + cos 31 cosec (90-31)

= cos 31 sin 31 + cos 31 sin 31

= 1 + 1

= 2 = RHS (proved)